GrandeKos.com on page Python

You can use the `os.path.basename()` function in Python's `os` module to get the basename

(filename) of a full path:

python

import os

full_path = "/path/to/file.txt"
basename = os.path.basename(full_path)
print(basename) # Output: file.txt

Alternatively, you can use string manipulation methods like slicing or splitting to

extract the filename from the full path:

python

full_path = "/path/to/file.txt"
filename = full_path.split("/")[-1]
print(filename) # Output: file.txt

However, using `os.path.basename()` is generally more concise and robust, as it handles

edge cases like trailing slashes or directory names with embedded slashes.

If you want to get the basename without any extension (e.g., "file" from "file.txt"), you

can use the `os.path.splitext()` function:

python

import os

full_path = "/path/to/file.txt"
filename, _ = os.path.splitext(os.path.basename(full_path))
print(filename) # Output: file

Note that in this example, we're using tuple unpacking to extract just the filename

(without extension) from the `splitext()` result.